9(2z+1)=9(9+7z)

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Solution for 9(2z+1)=9(9+7z) equation: 



9(2z+1)=9(9+7z)

We move all terms to the left:

9(2z+1)-(9(9+7z))=0

We add all the numbers together, and all the variables

9(2z+1)-(9(7z+9))=0

We multiply parentheses

18z-(9(7z+9))+9=0



We calculate terms in parentheses: -(9(7z+9)), so:

9(7z+9)

We multiply parentheses

63z+81

Back to the equation:

-(63z+81)



We get rid of parentheses

18z-63z-81+9=0

We add all the numbers together, and all the variables

-45z-72=0

We move all terms containing z to the left, all other terms to the right

-45z=72

z=72/-45

z=-1+3/5

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