9(2x-7)-5=9(x-4)+(4)

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Solution for 9(2x-7)-5=9(x-4)+(4) equation: 



9(2x-7)-5=9(x-4)+(4)

We move all terms to the left:

9(2x-7)-5-(9(x-4)+(4))=0

We multiply parentheses

18x-(9(x-4)+4)-63-5=0



We calculate terms in parentheses: -(9(x-4)+4), so:

9(x-4)+4

We multiply parentheses

9x-36+4

We add all the numbers together, and all the variables

9x-32

Back to the equation:

-(9x-32)



We add all the numbers together, and all the variables

18x-(9x-32)-68=0

We get rid of parentheses

18x-9x+32-68=0

We add all the numbers together, and all the variables

9x-36=0

We move all terms containing x to the left, all other terms to the right

9x=36

x=36/9

x=4

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