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9(2x-5)-6x=3(4x-15)
We move all terms to the left:
9(2x-5)-6x-(3(4x-15))=0
We add all the numbers together, and all the variables
-6x+9(2x-5)-(3(4x-15))=0
We multiply parentheses
-6x+18x-(3(4x-15))-45=0
We calculate terms in parentheses: -(3(4x-15)), so:We add all the numbers together, and all the variables
3(4x-15)
We multiply parentheses
12x-45
Back to the equation:
-(12x-45)
12x-(12x-45)-45=0
We get rid of parentheses
12x-12x+45-45=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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