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9(2x-1)-3x=3-(12+x)
We move all terms to the left:
9(2x-1)-3x-(3-(12+x))=0
We add all the numbers together, and all the variables
9(2x-1)-3x-(3-(x+12))=0
We add all the numbers together, and all the variables
-3x+9(2x-1)-(3-(x+12))=0
We multiply parentheses
-3x+18x-(3-(x+12))-9=0
We calculate terms in parentheses: -(3-(x+12)), so:We add all the numbers together, and all the variables
3-(x+12)
determiningTheFunctionDomain -(x+12)+3
We get rid of parentheses
-x-12+3
We add all the numbers together, and all the variables
-1x-9
Back to the equation:
-(-1x-9)
15x-(-1x-9)-9=0
We get rid of parentheses
15x+1x+9-9=0
We add all the numbers together, and all the variables
16x=0
x=0/16
x=0
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