9(2x+3)=3(7x-1)

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Solution for 9(2x+3)=3(7x-1) equation: 



9(2x+3)=3(7x-1)

We move all terms to the left:

9(2x+3)-(3(7x-1))=0

We multiply parentheses

18x-(3(7x-1))+27=0



We calculate terms in parentheses: -(3(7x-1)), so:

3(7x-1)

We multiply parentheses

21x-3

Back to the equation:

-(21x-3)



We get rid of parentheses

18x-21x+3+27=0

We add all the numbers together, and all the variables

-3x+30=0

We move all terms containing x to the left, all other terms to the right

-3x=-30

x=-30/-3

x=+10

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