9(2x+1)-5(3x-2)=63

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Solution for 9(2x+1)-5(3x-2)=63 equation: 



9(2x+1)-5(3x-2)=63

We move all terms to the left:

9(2x+1)-5(3x-2)-(63)=0

We multiply parentheses

18x-15x+9+10-63=0

We add all the numbers together, and all the variables

3x-44=0

We move all terms containing x to the left, all other terms to the right

3x=44

x=44/3

x=14+2/3

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