9(2t+1)-12=t-(t+2)

Solution for 9(2t+1)-12=t-(t+2) equation:

9(2t+1)-12=t-(t+2)

We move all terms to the left:

9(2t+1)-12-(t-(t+2))=0

We multiply parentheses

18t-(t-(t+2))+9-12=0


We calculate terms in parentheses: -(t-(t+2)), so:

t-(t+2)

We get rid of parentheses

t-t-2

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)


We add all the numbers together, and all the variables

18t-1=0

We move all terms containing t to the left, all other terms to the right

18t=1

t=1/18

t=1/18