9(2r+1)-3(4r+2)=6

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Solution for 9(2r+1)-3(4r+2)=6 equation: 



9(2r+1)-3(4r+2)=6

We move all terms to the left:

9(2r+1)-3(4r+2)-(6)=0

We multiply parentheses

18r-12r+9-6-6=0

We add all the numbers together, and all the variables

6r-3=0

We move all terms containing r to the left, all other terms to the right

6r=3

r=3/6

r=1/2

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