9(2n+3)=9(9n+3)+5

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Solution for 9(2n+3)=9(9n+3)+5 equation: 



9(2n+3)=9(9n+3)+5

We move all terms to the left:

9(2n+3)-(9(9n+3)+5)=0

We multiply parentheses

18n-(9(9n+3)+5)+27=0



We calculate terms in parentheses: -(9(9n+3)+5), so:

9(9n+3)+5

We multiply parentheses

81n+27+5

We add all the numbers together, and all the variables

81n+32

Back to the equation:

-(81n+32)



We get rid of parentheses

18n-81n-32+27=0

We add all the numbers together, and all the variables

-63n-5=0

We move all terms containing n to the left, all other terms to the right

-63n=5

n=5/-63

n=-5/63

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