9(2n+3)=9(7n+4)+8

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Solution for 9(2n+3)=9(7n+4)+8 equation: 



9(2n+3)=9(7n+4)+8

We move all terms to the left:

9(2n+3)-(9(7n+4)+8)=0

We multiply parentheses

18n-(9(7n+4)+8)+27=0



We calculate terms in parentheses: -(9(7n+4)+8), so:

9(7n+4)+8

We multiply parentheses

63n+36+8

We add all the numbers together, and all the variables

63n+44

Back to the equation:

-(63n+44)



We get rid of parentheses

18n-63n-44+27=0

We add all the numbers together, and all the variables

-45n-17=0

We move all terms containing n to the left, all other terms to the right

-45n=17

n=17/-45

n=-17/45

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