9(2k+3)+2=11(k-61/3)

Solution for 9(2k+3)+2=11(k-61/3) equation:

9(2k+3)+2=11(k-61/3)

We move all terms to the left:

9(2k+3)+2-(11(k-61/3))=0

We add all the numbers together, and all the variables

9(2k+3)-(11(+k-61/3))+2=0

We multiply parentheses

18k-(11(+k-61/3))+27+2=0

We multiply all the terms by the denominator


18k*3))-(11(+k-61+27*3))+2*3))=0

We add all the numbers together, and all the variables

18k*3))-(11(k+20))+2*3))=0

We add all the numbers together, and all the variables

18k*3))-(11(k=0

Wy multiply elements

54k^2=0

a = 54; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·54·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{108}=0$