9(2-j)+3(5+2j)=2(7-2j)-4)j-1)

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Solution for 9(2-j)+3(5+2j)=2(7-2j)-4)j-1) equation:



9(2-j)+3(5+2j)=2(7-2j)-4)j-1)
We move all terms to the left:
9(2-j)+3(5+2j)-(2(7-2j)-4)j-1))=0
We add all the numbers together, and all the variables
9(-1j+2)+3(2j+5)-(2(-2j+7)-4)j-1))=0
We add all the numbers together, and all the variables
9(-1j+2)+3(2j+5)-(2(-2j+7)-4)j=0
We multiply parentheses
-9j+6j-(2(-2j+7)-4)j+18+15=0
We add all the numbers together, and all the variables
-3j-(2(-2j+7)-4)j+33=0
We move all terms containing j to the left, all other terms to the right
-3j-(2(-2j+7)-4)j=-33

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