9(2-3x)-29=8x-(-23)

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Solution for 9(2-3x)-29=8x-(-23) equation: 



9(2-3x)-29=8x-(-23)

We move all terms to the left:

9(2-3x)-29-(8x-(-23))=0

We add all the numbers together, and all the variables

9(-3x+2)-(8x-(-23))-29=0

We multiply parentheses

-27x-(8x-(-23))+18-29=0



We calculate terms in parentheses: -(8x-(-23)), so:

8x-(-23)

We add all the numbers together, and all the variables

8x+23

Back to the equation:

-(8x+23)



We add all the numbers together, and all the variables

-27x-(8x+23)-11=0

We get rid of parentheses

-27x-8x-23-11=0

We add all the numbers together, and all the variables

-35x-34=0

We move all terms containing x to the left, all other terms to the right

-35x=34

x=34/-35

x=-34/35

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