9(2+3x)=459(2+3x)=45

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Solution for 9(2+3x)=459(2+3x)=45 equation: 



9(2+3x)=459(2+3x)=45

We move all terms to the left:

9(2+3x)-(459(2+3x))=0

We add all the numbers together, and all the variables

9(3x+2)-(459(3x+2))=0

We multiply parentheses

27x-(459(3x+2))+18=0



We calculate terms in parentheses: -(459(3x+2)), so:

459(3x+2)

We multiply parentheses

1377x+918

Back to the equation:

-(1377x+918)



We get rid of parentheses

27x-1377x-918+18=0

We add all the numbers together, and all the variables

-1350x-900=0

We move all terms containing x to the left, all other terms to the right

-1350x=900

x=900/-1350

x=-2/3

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