9(12t-12)-3=10(6t-18)+11

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Solution for 9(12t-12)-3=10(6t-18)+11 equation: 



9(12t-12)-3=10(6t-18)+11

We move all terms to the left:

9(12t-12)-3-(10(6t-18)+11)=0

We multiply parentheses

108t-(10(6t-18)+11)-108-3=0



We calculate terms in parentheses: -(10(6t-18)+11), so:

10(6t-18)+11

We multiply parentheses

60t-180+11

We add all the numbers together, and all the variables

60t-169

Back to the equation:

-(60t-169)



We add all the numbers together, and all the variables

108t-(60t-169)-111=0

We get rid of parentheses

108t-60t+169-111=0

We add all the numbers together, and all the variables

48t+58=0

We move all terms containing t to the left, all other terms to the right

48t=-58

t=-58/48

t=-1+5/24

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