9(1/3x+1)=9(x+23/9)

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Solution for 9(1/3x+1)=9(x+23/9) equation: 



9(1/3x+1)=9(x+23/9)

We move all terms to the left:

9(1/3x+1)-(9(x+23/9))=0



Domain of the equation: 3x+1)!=0

x∈R



We add all the numbers together, and all the variables

9(1/3x+1)-(9(+x+23/9))=0

We multiply parentheses

9x-(9(+x+23/9))+9=0

We multiply all the terms by the denominator


9x*9))-(9(+x+23+9*9))=0

We add all the numbers together, and all the variables

9x*9))-(9(x+104))=0

We add all the numbers together, and all the variables

9x*9))-(9(x=0

Wy multiply elements

81x^2=0

a = 81; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·81·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{162}=0$

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