9(1-x)=6(2x+1)

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Solution for 9(1-x)=6(2x+1) equation: 



9(1-x)=6(2x+1)

We move all terms to the left:

9(1-x)-(6(2x+1))=0

We add all the numbers together, and all the variables

9(-1x+1)-(6(2x+1))=0

We multiply parentheses

-9x-(6(2x+1))+9=0



We calculate terms in parentheses: -(6(2x+1)), so:

6(2x+1)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

-9x-12x-6+9=0

We add all the numbers together, and all the variables

-21x+3=0

We move all terms containing x to the left, all other terms to the right

-21x=-3

x=-3/-21

x=1/7

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