9(-3f-18)=6+f

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Solution for 9(-3f-18)=6+f equation: 



9(-3f-18)=6+f

We move all terms to the left:

9(-3f-18)-(6+f)=0

We add all the numbers together, and all the variables

9(-3f-18)-(f+6)=0

We multiply parentheses

-27f-(f+6)-162=0

We get rid of parentheses

-27f-f-6-162=0

We add all the numbers together, and all the variables

-28f-168=0

We move all terms containing f to the left, all other terms to the right

-28f=168

f=168/-28

f=-6

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