8z-7(z+2)=4(z-7)-3z

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Solution for 8z-7(z+2)=4(z-7)-3z equation:


Simplifying
8z + -7(z + 2) = 4(z + -7) + -3z

Reorder the terms:
8z + -7(2 + z) = 4(z + -7) + -3z
8z + (2 * -7 + z * -7) = 4(z + -7) + -3z
8z + (-14 + -7z) = 4(z + -7) + -3z

Reorder the terms:
-14 + 8z + -7z = 4(z + -7) + -3z

Combine like terms: 8z + -7z = 1z
-14 + 1z = 4(z + -7) + -3z

Reorder the terms:
-14 + 1z = 4(-7 + z) + -3z
-14 + 1z = (-7 * 4 + z * 4) + -3z
-14 + 1z = (-28 + 4z) + -3z

Combine like terms: 4z + -3z = 1z
-14 + 1z = -28 + 1z

Add '-1z' to each side of the equation.
-14 + 1z + -1z = -28 + 1z + -1z

Combine like terms: 1z + -1z = 0
-14 + 0 = -28 + 1z + -1z
-14 = -28 + 1z + -1z

Combine like terms: 1z + -1z = 0
-14 = -28 + 0
-14 = -28

Solving
-14 = -28

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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