8z-4(z-4)=12(z+1)+8

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Solution for 8z-4(z-4)=12(z+1)+8 equation: 


Simplifying
8z + -4(z + -4) = 12(z + 1) + 8

Reorder the terms:
8z + -4(-4 + z) = 12(z + 1) + 8
8z + (-4 * -4 + z * -4) = 12(z + 1) + 8
8z + (16 + -4z) = 12(z + 1) + 8

Reorder the terms:
16 + 8z + -4z = 12(z + 1) + 8

Combine like terms: 8z + -4z = 4z
16 + 4z = 12(z + 1) + 8

Reorder the terms:
16 + 4z = 12(1 + z) + 8
16 + 4z = (1 * 12 + z * 12) + 8
16 + 4z = (12 + 12z) + 8

Reorder the terms:
16 + 4z = 12 + 8 + 12z

Combine like terms: 12 + 8 = 20
16 + 4z = 20 + 12z

Solving
16 + 4z = 20 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
16 + 4z + -12z = 20 + 12z + -12z

Combine like terms: 4z + -12z = -8z
16 + -8z = 20 + 12z + -12z

Combine like terms: 12z + -12z = 0
16 + -8z = 20 + 0
16 + -8z = 20

Add '-16' to each side of the equation.
16 + -16 + -8z = 20 + -16

Combine like terms: 16 + -16 = 0
0 + -8z = 20 + -16
-8z = 20 + -16

Combine like terms: 20 + -16 = 4
-8z = 4

Divide each side by '-8'.
z = -0.5

Simplifying
z = -0.5

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