8z+42+16z+58=2(15z+47)

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Solution for 8z+42+16z+58=2(15z+47) equation: 



8z+42+16z+58=2(15z+47)

We move all terms to the left:

8z+42+16z+58-(2(15z+47))=0

We add all the numbers together, and all the variables

24z-(2(15z+47))+100=0



We calculate terms in parentheses: -(2(15z+47)), so:

2(15z+47)

We multiply parentheses

30z+94

Back to the equation:

-(30z+94)



We get rid of parentheses

24z-30z-94+100=0

We add all the numbers together, and all the variables

-6z+6=0

We move all terms containing z to the left, all other terms to the right

-6z=-6

z=-6/-6

z=1

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