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8y^2-14y-15=0
a = 8; b = -14; c = -15;
Δ = b2-4ac
Δ = -142-4·8·(-15)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-26}{2*8}=\frac{-12}{16} =-3/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+26}{2*8}=\frac{40}{16} =2+1/2 $
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