8y2+y/4y=25/4

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Solution for 8y2+y/4y=25/4 equation: 



8y^2+y/4y=25/4

We move all terms to the left:

8y^2+y/4y-(25/4)=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



We add all the numbers together, and all the variables

8y^2+y/4y-(+25/4)=0

We get rid of parentheses

8y^2+y/4y-25/4=0

We calculate fractions


8y^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{16}=0$

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