8y2+34y-36=0

Solution for 8y2+34y-36=0 equation:

8y^2+34y-36=0

a = 8; b = 34; c = -36;
Δ = b2-4ac
Δ = 342-4·8·(-36)
Δ = 2308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2308}=\sqrt{4*577}=\sqrt{4}*\sqrt{577}=2\sqrt{577}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{577}}{2*8}=\frac{-34-2\sqrt{577}}{16}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{577}}{2*8}=\frac{-34+2\sqrt{577}}{16}
$