8y-7(y-4)+4=32

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Solution for 8y-7(y-4)+4=32 equation:


8y-7(y-4)+4=32

We simplify the equation to the form, which is simple to understand 
8y-7(y-4)+4=32

Reorder the terms in parentheses
8y+(-7y+28)+4=32

Remove unnecessary parentheses
+8y-7y+28+4=+32

We move all terms containing y to the left and all other terms to the right. 
+8y-7y=+32-28-4

We simplify left and right side of the equation. 
+1y=0

We divide both sides of the equation by 1 to get y. 
y=0

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