8y-40=-3(4-5y)

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Solution for 8y-40=-3(4-5y) equation: 



8y-40=-3(4-5y)

We move all terms to the left:

8y-40-(-3(4-5y))=0

We add all the numbers together, and all the variables

8y-(-3(-5y+4))-40=0



We calculate terms in parentheses: -(-3(-5y+4)), so:

-3(-5y+4)

We multiply parentheses

15y-12

Back to the equation:

-(15y-12)



We get rid of parentheses

8y-15y+12-40=0

We add all the numbers together, and all the variables

-7y-28=0

We move all terms containing y to the left, all other terms to the right

-7y=28

y=28/-7

y=-4

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