8y-4+2y=10(2y-3)

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Solution for 8y-4+2y=10(2y-3) equation: 



8y-4+2y=10(2y-3)

We move all terms to the left:

8y-4+2y-(10(2y-3))=0

We add all the numbers together, and all the variables

10y-(10(2y-3))-4=0



We calculate terms in parentheses: -(10(2y-3)), so:

10(2y-3)

We multiply parentheses

20y-30

Back to the equation:

-(20y-30)



We get rid of parentheses

10y-20y+30-4=0

We add all the numbers together, and all the variables

-10y+26=0

We move all terms containing y to the left, all other terms to the right

-10y=-26

y=-26/-10

y=2+3/5

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