8y-30-2y=8(y-5)C

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Solution for 8y-30-2y=8(y-5)C equation: 



8y-30-2y=8(y-5)

We move all terms to the left:

8y-30-2y-(8(y-5))=0

We add all the numbers together, and all the variables

6y-(8(y-5))-30=0



We calculate terms in parentheses: -(8(y-5)), so:

8(y-5)

We multiply parentheses

8y-40

Back to the equation:

-(8y-40)



We get rid of parentheses

6y-8y+40-30=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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