8y-20=4(3y+10)

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Solution for 8y-20=4(3y+10) equation: 



8y-20=4(3y+10)

We move all terms to the left:

8y-20-(4(3y+10))=0



We calculate terms in parentheses: -(4(3y+10)), so:

4(3y+10)

We multiply parentheses

12y+40

Back to the equation:

-(12y+40)



We get rid of parentheses

8y-12y-40-20=0

We add all the numbers together, and all the variables

-4y-60=0

We move all terms containing y to the left, all other terms to the right

-4y=60

y=60/-4

y=-15

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