8y-2+2(4y+3)=2(y+6)

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Solution for 8y-2+2(4y+3)=2(y+6) equation: 



8y-2+2(4y+3)=2(y+6)

We move all terms to the left:

8y-2+2(4y+3)-(2(y+6))=0

We multiply parentheses

8y+8y-(2(y+6))+6-2=0



We calculate terms in parentheses: -(2(y+6)), so:

2(y+6)

We multiply parentheses

2y+12

Back to the equation:

-(2y+12)



We add all the numbers together, and all the variables

16y-(2y+12)+4=0

We get rid of parentheses

16y-2y-12+4=0

We add all the numbers together, and all the variables

14y-8=0

We move all terms containing y to the left, all other terms to the right

14y=8

y=8/14

y=4/7

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