8y-10=3(6-2y)

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Solution for 8y-10=3(6-2y) equation: 



8y-10=3(6-2y)

We move all terms to the left:

8y-10-(3(6-2y))=0

We add all the numbers together, and all the variables

8y-(3(-2y+6))-10=0



We calculate terms in parentheses: -(3(-2y+6)), so:

3(-2y+6)

We multiply parentheses

-6y+18

Back to the equation:

-(-6y+18)



We get rid of parentheses

8y+6y-18-10=0

We add all the numbers together, and all the variables

14y-28=0

We move all terms containing y to the left, all other terms to the right

14y=28

y=28/14

y=2

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