8y-(6+2y)=2(y-9)

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Solution for 8y-(6+2y)=2(y-9) equation: 



8y-(6+2y)=2(y-9)

We move all terms to the left:

8y-(6+2y)-(2(y-9))=0

We add all the numbers together, and all the variables

8y-(2y+6)-(2(y-9))=0

We get rid of parentheses

8y-2y-(2(y-9))-6=0



We calculate terms in parentheses: -(2(y-9)), so:

2(y-9)

We multiply parentheses

2y-18

Back to the equation:

-(2y-18)



We add all the numbers together, and all the variables

6y-(2y-18)-6=0

We get rid of parentheses

6y-2y+18-6=0

We add all the numbers together, and all the variables

4y+12=0

We move all terms containing y to the left, all other terms to the right

4y=-12

y=-12/4

y=-3

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