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8y-(4y+24)=2-(6y-3)
We move all terms to the left:
8y-(4y+24)-(2-(6y-3))=0
We get rid of parentheses
8y-4y-(2-(6y-3))-24=0
We calculate terms in parentheses: -(2-(6y-3)), so:We add all the numbers together, and all the variables
2-(6y-3)
determiningTheFunctionDomain -(6y-3)+2
We get rid of parentheses
-6y+3+2
We add all the numbers together, and all the variables
-6y+5
Back to the equation:
-(-6y+5)
4y-(-6y+5)-24=0
We get rid of parentheses
4y+6y-5-24=0
We add all the numbers together, and all the variables
10y-29=0
We move all terms containing y to the left, all other terms to the right
10y=29
y=29/10
y=2+9/10
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