8y-(4-2y)=6(y+1)

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Solution for 8y-(4-2y)=6(y+1) equation: 



8y-(4-2y)=6(y+1)

We move all terms to the left:

8y-(4-2y)-(6(y+1))=0

We add all the numbers together, and all the variables

8y-(-2y+4)-(6(y+1))=0

We get rid of parentheses

8y+2y-(6(y+1))-4=0



We calculate terms in parentheses: -(6(y+1)), so:

6(y+1)

We multiply parentheses

6y+6

Back to the equation:

-(6y+6)



We add all the numbers together, and all the variables

10y-(6y+6)-4=0

We get rid of parentheses

10y-6y-6-4=0

We add all the numbers together, and all the variables

4y-10=0

We move all terms containing y to the left, all other terms to the right

4y=10

y=10/4

y=2+1/2

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