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8y+5-7(2y-1)=4(y-1))
We move all terms to the left:
8y+5-7(2y-1)-(4(y-1)))=0
We multiply parentheses
8y-14y-(4(y-1)))+5+7=0
We add all the numbers together, and all the variables
-6y-(4(y-1)))+5+7=0
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