8y+32=-4(y-5)

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Solution for 8y+32=-4(y-5) equation: 



8y+32=-4(y-5)

We move all terms to the left:

8y+32-(-4(y-5))=0



We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)



We get rid of parentheses

8y+4y-20+32=0

We add all the numbers together, and all the variables

12y+12=0

We move all terms containing y to the left, all other terms to the right

12y=-12

y=-12/12

y=-1

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