8y+2(y-5)=5(y+1)-4

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Solution for 8y+2(y-5)=5(y+1)-4 equation: 


Simplifying
8y + 2(y + -5) = 5(y + 1) + -4

Reorder the terms:
8y + 2(-5 + y) = 5(y + 1) + -4
8y + (-5 * 2 + y * 2) = 5(y + 1) + -4
8y + (-10 + 2y) = 5(y + 1) + -4

Reorder the terms:
-10 + 8y + 2y = 5(y + 1) + -4

Combine like terms: 8y + 2y = 10y
-10 + 10y = 5(y + 1) + -4

Reorder the terms:
-10 + 10y = 5(1 + y) + -4
-10 + 10y = (1 * 5 + y * 5) + -4
-10 + 10y = (5 + 5y) + -4

Reorder the terms:
-10 + 10y = 5 + -4 + 5y

Combine like terms: 5 + -4 = 1
-10 + 10y = 1 + 5y

Solving
-10 + 10y = 1 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
-10 + 10y + -5y = 1 + 5y + -5y

Combine like terms: 10y + -5y = 5y
-10 + 5y = 1 + 5y + -5y

Combine like terms: 5y + -5y = 0
-10 + 5y = 1 + 0
-10 + 5y = 1

Add '10' to each side of the equation.
-10 + 10 + 5y = 1 + 10

Combine like terms: -10 + 10 = 0
0 + 5y = 1 + 10
5y = 1 + 10

Combine like terms: 1 + 10 = 11
5y = 11

Divide each side by '5'.
y = 2.2

Simplifying
y = 2.2

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