8y+2(y-4)=6(y+1)-3

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Solution for 8y+2(y-4)=6(y+1)-3 equation:


Simplifying
8y + 2(y + -4) = 6(y + 1) + -3

Reorder the terms:
8y + 2(-4 + y) = 6(y + 1) + -3
8y + (-4 * 2 + y * 2) = 6(y + 1) + -3
8y + (-8 + 2y) = 6(y + 1) + -3

Reorder the terms:
-8 + 8y + 2y = 6(y + 1) + -3

Combine like terms: 8y + 2y = 10y
-8 + 10y = 6(y + 1) + -3

Reorder the terms:
-8 + 10y = 6(1 + y) + -3
-8 + 10y = (1 * 6 + y * 6) + -3
-8 + 10y = (6 + 6y) + -3

Reorder the terms:
-8 + 10y = 6 + -3 + 6y

Combine like terms: 6 + -3 = 3
-8 + 10y = 3 + 6y

Solving
-8 + 10y = 3 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-8 + 10y + -6y = 3 + 6y + -6y

Combine like terms: 10y + -6y = 4y
-8 + 4y = 3 + 6y + -6y

Combine like terms: 6y + -6y = 0
-8 + 4y = 3 + 0
-8 + 4y = 3

Add '8' to each side of the equation.
-8 + 8 + 4y = 3 + 8

Combine like terms: -8 + 8 = 0
0 + 4y = 3 + 8
4y = 3 + 8

Combine like terms: 3 + 8 = 11
4y = 11

Divide each side by '4'.
y = 2.75

Simplifying
y = 2.75

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