8y+2(y-4)=5(y+1)-3

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Solution for 8y+2(y-4)=5(y+1)-3 equation: 


Simplifying
8y + 2(y + -4) = 5(y + 1) + -3

Reorder the terms:
8y + 2(-4 + y) = 5(y + 1) + -3
8y + (-4 * 2 + y * 2) = 5(y + 1) + -3
8y + (-8 + 2y) = 5(y + 1) + -3

Reorder the terms:
-8 + 8y + 2y = 5(y + 1) + -3

Combine like terms: 8y + 2y = 10y
-8 + 10y = 5(y + 1) + -3

Reorder the terms:
-8 + 10y = 5(1 + y) + -3
-8 + 10y = (1 * 5 + y * 5) + -3
-8 + 10y = (5 + 5y) + -3

Reorder the terms:
-8 + 10y = 5 + -3 + 5y

Combine like terms: 5 + -3 = 2
-8 + 10y = 2 + 5y

Solving
-8 + 10y = 2 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
-8 + 10y + -5y = 2 + 5y + -5y

Combine like terms: 10y + -5y = 5y
-8 + 5y = 2 + 5y + -5y

Combine like terms: 5y + -5y = 0
-8 + 5y = 2 + 0
-8 + 5y = 2

Add '8' to each side of the equation.
-8 + 8 + 5y = 2 + 8

Combine like terms: -8 + 8 = 0
0 + 5y = 2 + 8
5y = 2 + 8

Combine like terms: 2 + 8 = 10
5y = 10

Divide each side by '5'.
y = 2

Simplifying
y = 2

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