8y+2(y-3)=4(y+1)-3

Solution for 8y+2(y-3)=4(y+1)-3 equation:

Simplifying
8y + 2(y + -3) = 4(y + 1) + -3

Reorder the terms:
8y + 2(-3 + y) = 4(y + 1) + -3
8y + (-3 * 2 + y * 2) = 4(y + 1) + -3
8y + (-6 + 2y) = 4(y + 1) + -3

Reorder the terms:
-6 + 8y + 2y = 4(y + 1) + -3

Combine like terms: 8y + 2y = 10y
-6 + 10y = 4(y + 1) + -3

Reorder the terms:
-6 + 10y = 4(1 + y) + -3
-6 + 10y = (1 * 4 + y * 4) + -3
-6 + 10y = (4 + 4y) + -3

Reorder the terms:
-6 + 10y = 4 + -3 + 4y

Combine like terms: 4 + -3 = 1
-6 + 10y = 1 + 4y

Solving
-6 + 10y = 1 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-6 + 10y + -4y = 1 + 4y + -4y

Combine like terms: 10y + -4y = 6y
-6 + 6y = 1 + 4y + -4y

Combine like terms: 4y + -4y = 0
-6 + 6y = 1 + 0
-6 + 6y = 1

Add '6' to each side of the equation.
-6 + 6 + 6y = 1 + 6

Combine like terms: -6 + 6 = 0
0 + 6y = 1 + 6
6y = 1 + 6

Combine like terms: 1 + 6 = 7
6y = 7

Divide each side by '6'.
y = 1.166666667

Simplifying
y = 1.166666667