8y+12-3y-7=6y-5y-3

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Solution for 8y+12-3y-7=6y-5y-3 equation: 



8y+12-3y-7=6y-5y-3

We move all terms to the left:

8y+12-3y-7-(6y-5y-3)=0

We add all the numbers together, and all the variables

8y-3y-(y-3)+12-7=0

We add all the numbers together, and all the variables

5y-(y-3)+5=0

We get rid of parentheses

5y-y+3+5=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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