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8x^2=3(x2+15)
We move all terms to the left:
8x^2-(3(x2+15))=0
We add all the numbers together, and all the variables
8x^2-(3(+x^2+15))=0
We calculate terms in parentheses: -(3(+x^2+15)), so:We get rid of parentheses
3(+x^2+15)
We multiply parentheses
3x^2+45
Back to the equation:
-(3x^2+45)
8x^2-3x^2-45=0
We add all the numbers together, and all the variables
5x^2-45=0
a = 5; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·5·(-45)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*5}=\frac{-30}{10} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*5}=\frac{30}{10} =3 $
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