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8x^2=16106
We move all terms to the left:
8x^2-(16106)=0
a = 8; b = 0; c = -16106;
Δ = b2-4ac
Δ = 02-4·8·(-16106)
Δ = 515392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{515392}=\sqrt{64*8053}=\sqrt{64}*\sqrt{8053}=8\sqrt{8053}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{8053}}{2*8}=\frac{0-8\sqrt{8053}}{16} =-\frac{8\sqrt{8053}}{16} =-\frac{\sqrt{8053}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{8053}}{2*8}=\frac{0+8\sqrt{8053}}{16} =\frac{8\sqrt{8053}}{16} =\frac{\sqrt{8053}}{2} $
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