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8x^2=11x+4
We move all terms to the left:
8x^2-(11x+4)=0
We get rid of parentheses
8x^2-11x-4=0
a = 8; b = -11; c = -4;
Δ = b2-4ac
Δ = -112-4·8·(-4)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{249}}{2*8}=\frac{11-\sqrt{249}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{249}}{2*8}=\frac{11+\sqrt{249}}{16} $
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