If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2-8x=6
We move all terms to the left:
8x^2-8x-(6)=0
a = 8; b = -8; c = -6;
Δ = b2-4ac
Δ = -82-4·8·(-6)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16}{2*8}=\frac{-8}{16} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16}{2*8}=\frac{24}{16} =1+1/2 $
| r-52/9=4 | | 19+6w=73 | | 3+1/y=1/5 | | 73=9+8s | | 24=-4n-4n | | 24=-4-4n | | 1/4x+28=3/5x | | 7x+4=2x-7 | | 3/16-5/4=g | | 5x+1=1-6x | | 6n+5=8n+1 | | 4210/x=5 | | 27=2(2w+3+w) | | 10x=40-3 | | 4x+15=-5-12 | | -1/3y-2=4 | | 10x=4(10)-3 | | Y=-6(x+4)^2-3 | | Y=-5x2+10x+15 | | 1/2n=2=8 | | (−10x−7)−(3x−10)=(−10x−7)−(3x−10) | | 4j−5=11 | | (−10x−7)−(3x−10)=(−10x−7)−(3x−10)= | | 10x=4×-3 | | 10x=4×+3 | | 4/5=x-3/10 | | 2x+2=1- | | 90=32+3x | | 3x+2x-6=25 | | 90=3x+32 | | 90=39+3x | | 10x-4.5+3x=2x-1.1 |