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8x^2+6x^2-44=0
We add all the numbers together, and all the variables
14x^2-44=0
a = 14; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·14·(-44)
Δ = 2464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2464}=\sqrt{16*154}=\sqrt{16}*\sqrt{154}=4\sqrt{154}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{154}}{2*14}=\frac{0-4\sqrt{154}}{28} =-\frac{4\sqrt{154}}{28} =-\frac{\sqrt{154}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{154}}{2*14}=\frac{0+4\sqrt{154}}{28} =\frac{4\sqrt{154}}{28} =\frac{\sqrt{154}}{7} $
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