8x-9=(3x+1)+(4x-5)

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Solution for 8x-9=(3x+1)+(4x-5) equation: 



8x-9=(3x+1)+(4x-5)

We move all terms to the left:

8x-9-((3x+1)+(4x-5))=0



We calculate terms in parentheses: -((3x+1)+(4x-5)), so:

(3x+1)+(4x-5)

We get rid of parentheses

3x+4x+1-5

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We get rid of parentheses

8x-7x+4-9=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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