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8x-6/5x=2
We move all terms to the left:
8x-6/5x-(2)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
8x*5x-2*5x-6=0
Wy multiply elements
40x^2-10x-6=0
a = 40; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·40·(-6)
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{265}}{2*40}=\frac{10-2\sqrt{265}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{265}}{2*40}=\frac{10+2\sqrt{265}}{80} $
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