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8x-5+2x=2(3x+5)+4x
We move all terms to the left:
8x-5+2x-(2(3x+5)+4x)=0
We add all the numbers together, and all the variables
10x-(2(3x+5)+4x)-5=0
We calculate terms in parentheses: -(2(3x+5)+4x), so:We get rid of parentheses
2(3x+5)+4x
We add all the numbers together, and all the variables
4x+2(3x+5)
We multiply parentheses
4x+6x+10
We add all the numbers together, and all the variables
10x+10
Back to the equation:
-(10x+10)
10x-10x-10-5=0
We add all the numbers together, and all the variables
-15!=0
There is no solution for this equation
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