8x-4x+8=8(x-2)

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Solution for 8x-4x+8=8(x-2) equation: 



8x-4x+8=8(x-2)

We move all terms to the left:

8x-4x+8-(8(x-2))=0

We add all the numbers together, and all the variables

4x-(8(x-2))+8=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

4x-8x+16+8=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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